Community Medicine (PSM) · Biostatistics (Measures of Central Tendency, Tests of Significance, Sampling)

In a study comparing 5-year survival rates among 4 different chemotherapy regimens, which statistical test is MOST appropriate if survival times are not normally distributed?

  • A One-way ANOVA
  • B Paired t-test
  • C Pearson's chi-square test
  • D Kruskal-Wallis test
Correct answer: D. Kruskal-Wallis test

Explanation

The Kruskal-Wallis test is the non-parametric equivalent of one-way ANOVA, used when the assumption of normality is violated and there are more than two independent groups. ANOVA requires normally distributed data. The paired t-test compares two related (not independent) groups. Chi-square is for categorical data, not continuous survival times. Kruskal-Wallis ranks the data across groups and tests whether samples originate from the same distribution.

Reference: Park's Textbook of Preventive and Social Medicine, 27th ed.

High-yield for: NEET PGINI-CETNExTFMGEUSMLEPLABMRCP

Written and medically reviewed by the StethoPrep medical team.

Sponsored

Want to test yourself?

Create a free account for timed mock tests, mistake tracking, and FSRS spaced-repetition revision across 23,000+ MCQs.

Start free → Log in

More Biostatistics (Measures of Central Tendency, Tests of Significance, Sampling) MCQs

See all Biostatistics (Measures of Central Tendency, Tests of Significance, Sampling) MCQs →