Physiology · Special Senses and Sensory Receptors

In phototransduction, when a photon is absorbed by rhodopsin in a rod photoreceptor, the cell hyperpolarises rather than depolarises. Which sequence of events explains this paradoxical hyperpolarisation?

  • A Activated rhodopsin (metarhodopsin II) activates transducin (Gt), which activates PDE6, hydrolysing cGMP; cGMP-gated cation channels close; Na⁺ and Ca²⁺ entry ceases; K⁺ efflux via open K⁺ channels hyperpolarises the cell
  • B Photon absorption activates rhodopsin, which directly opens Cl⁻ channels, causing Cl⁻ influx and hyperpolarisation
  • C Activated rhodopsin inhibits guanylate cyclase, reducing cGMP; cGMP-gated Na⁺ channels open in the dark are ligand-gated and close when cGMP falls, causing hyperpolarisation
  • D Photon energy is transduced into a H⁺ gradient by opsin-linked proton pumps, acidifying the cytoplasm and activating inward-rectifier K⁺ channels
Correct answer: A. Activated rhodopsin (metarhodopsin II) activates transducin (Gt), which activates PDE6, hydrolysing cGMP; cGMP-gated cation channels close; Na⁺ and Ca²⁺ entry ceases; K⁺ efflux via open K⁺ channels hyperpolarises the cell

Explanation

Phototransduction: Rhodopsin → (photon) → Metarhodopsin II → activates Gt (transducin) → activates phosphodiesterase-6 (PDE6) → rapidly hydrolyses cGMP → [cGMP]i falls → cGMP-gated non-selective cation channels (CNG channels, which were held open in the dark by cGMP) close → Na⁺ and Ca²⁺ influx ceases while K⁺ continues to exit through open K⁺ leak channels → net hyperpolarisation (from ~-40 mV in dark to ~-70 mV in light). This reduces glutamate release from the rod terminal onto bipolar cells. Option C incorrectly states that rhodopsin inhibits guanylate cyclase; that is a recovery mechanism (GC activation by GCAP after Ca²⁺ falls). PDE6 activation, not GC inhibition, is the primary event.

Reference: Guyton & Hall, Textbook of Medical Physiology, 14th ed.

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