Physiology · Reproductive Physiology

A 26-year-old female patient has FSH: 18 IU/L (elevated), LH: 22 IU/L (elevated), AMH: 0.1 ng/mL (very low), and antral follicle count of 2. These findings are consistent with premature ovarian insufficiency (POI). What is the primary pathophysiological mechanism of the elevated gonadotropins in this condition?

  • A Autoantibodies against FSH receptors block FSH action, causing compensatory FSH hypersecretion
  • B GnRH pulse frequency increases due to reduced hypothalamic estrogen receptor expression
  • C Elevated prolactin from associated autoimmunity reduces dopaminergic inhibition of FSH
  • D Loss of follicular granulosa cells eliminates inhibin B and estradiol, removing negative feedback on pituitary FSH and LH secretion
Correct answer: D. Loss of follicular granulosa cells eliminates inhibin B and estradiol, removing negative feedback on pituitary FSH and LH secretion

Explanation

In premature ovarian insufficiency (POI), depletion of the follicular pool means absence of granulosa cells, which normally produce inhibin B (FSH-specific inhibitor) and estradiol (LH and FSH inhibitor via negative feedback). With loss of these feedback signals, the hypothalamo-pituitary axis is unrestrained, and both FSH (primarily inhibin-sensitive) and LH (primarily estradiol-sensitive) rise markedly. Low AMH reflects absent granulosa cell mass. The hypergonadotropic pattern (high FSH/LH + low estrogen) distinguishes primary ovarian failure from hypogonadotropic hypogonadism (low FSH/LH).

Reference: Guyton & Hall, Textbook of Medical Physiology, 14th ed.

High-yield for: NEET PGINI-CETNExTFMGEUSMLEPLABMRCP

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