Physiology · Muscle Physiology (Skeletal, Smooth, Motor Unit)

The force–velocity relationship of skeletal muscle (Hill equation) shows that maximum velocity of shortening (Vmax) occurs at zero external load, and maximum isometric force (P₀) occurs at zero velocity. What is the physiological basis of the inverse relationship between force and velocity?

  • A At high loads, more ATP is consumed per cross-bridge cycle, depleting energy and slowing cycling rate
  • B The rate of cross-bridge attachment is load-independent, but the rate of cross-bridge detachment increases at lower loads, allowing faster cycling without reducing the number of attached bridges
  • C Titin (connectin) protein stiffness prevents rapid shortening under high loads by acting as a passive brake
  • D Under high load, cross-bridges must generate more force per cycle but cannot increase force without prolonging the attached state, reducing cycling rate and shortening velocity
Correct answer: D. Under high load, cross-bridges must generate more force per cycle but cannot increase force without prolonging the attached state, reducing cycling rate and shortening velocity

Explanation

At high external loads, each cross-bridge must sustain greater force during the attached (power-stroke) state. For a cross-bridge to complete its power stroke against higher resistance, it must remain attached longer, reducing the turnover rate (cycles per second) and thus shortening velocity. At zero load, cross-bridges complete power strokes quickly and detach rapidly (fast cycling, high Vmax). The maximum force (P₀) is achieved in an isometric contraction where all cross-bridges contribute force simultaneously without net shortening. This relationship is governed by the kinetics of myosin ATPase and is fundamental to understanding cardiac contractility and smooth muscle mechanics.

Reference: Guyton & Hall, Textbook of Medical Physiology, 14th ed.

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