The force–velocity relationship of skeletal muscle (Hill equation) shows that maximum velocity of shortening (Vmax) occurs at zero external load, and maximum isometric force (P₀) occurs at zero velocity. What is the physiological basis of the inverse relationship between force and velocity?
- A At high loads, more ATP is consumed per cross-bridge cycle, depleting energy and slowing cycling rate
- B The rate of cross-bridge attachment is load-independent, but the rate of cross-bridge detachment increases at lower loads, allowing faster cycling without reducing the number of attached bridges
- C Titin (connectin) protein stiffness prevents rapid shortening under high loads by acting as a passive brake
- D Under high load, cross-bridges must generate more force per cycle but cannot increase force without prolonging the attached state, reducing cycling rate and shortening velocity ✓
Explanation
At high external loads, each cross-bridge must sustain greater force during the attached (power-stroke) state. For a cross-bridge to complete its power stroke against higher resistance, it must remain attached longer, reducing the turnover rate (cycles per second) and thus shortening velocity. At zero load, cross-bridges complete power strokes quickly and detach rapidly (fast cycling, high Vmax). The maximum force (P₀) is achieved in an isometric contraction where all cross-bridges contribute force simultaneously without net shortening. This relationship is governed by the kinetics of myosin ATPase and is fundamental to understanding cardiac contractility and smooth muscle mechanics.
Reference: Guyton & Hall, Textbook of Medical Physiology, 14th ed.
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