Physiology · Calcium Homeostasis and Bone Metabolism

Parathyroid hormone (PTH) paradoxically increases both bone resorption (via osteoclasts) and bone formation (when given intermittently as teriparatide). Which cellular mechanism explains how PTH promotes osteoclast-mediated bone resorption, given that osteoclasts lack PTH receptors?

  • A PTH activates calcitonin receptors on osteoblasts, which release cathepsin K to dissolve bone matrix
  • B PTH increases urinary calcium loss, which signals osteoclasts to release calcium from bone
  • C PTH binds osteoblasts → upregulates RANKL expression on osteoblast surface → RANKL binds RANK on osteoclast precursors → osteoclastogenesis and osteoclast activation
  • D PTH directly enters osteoclasts via transcytosis and activates intracellular PKA
Correct answer: C. PTH binds osteoblasts → upregulates RANKL expression on osteoblast surface → RANKL binds RANK on osteoclast precursors → osteoclastogenesis and osteoclast activation

Explanation

Osteoclasts lack PTH1R receptors. PTH acts indirectly: it binds osteoblasts and stromal cells via PTH1R (Gs-coupled) → cAMP → PKA → increases RANKL expression and decreases OPG (osteoprotegerin, the decoy receptor for RANKL). The net rise in RANKL/OPG ratio allows RANKL to bind RANK on osteoclast precursors and mature osteoclasts, driving osteoclastogenesis, osteoclast activation, and bone resorption. Bisphosphonates and denosumab (anti-RANKL antibody) exploit this pathway. Intermittent PTH (teriparatide) anabolically activates osteoblasts when signalling is transient rather than continuous.

Reference: Guyton & Hall, Textbook of Medical Physiology, 14th ed.

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