Ophthalmology · Optics and Refraction (Myopia, Hypermetropia, Astigmatism)

A myopic spectacle lens of -10.00 DS is moved from a vertex distance of 12 mm to 15 mm. The effective power of the lens at the new position is approximately:

  • A -10.30 DS
  • B -10.00 DS (no change)
  • C -9.70 DS
  • D -9.50 DS
Correct answer: C. -9.70 DS

Explanation

For a minus lens, moving it further from the eye (increasing vertex distance) makes it less effective (less negative). Using the vertex power formula: F_new = F / (1 - dF), where d = 0.003 m and F = -10. F_new = -10 / (1 - 0.003 × -10) = -10 / 1.03 = -9.70 D. A common trap is adding the correction instead of subtracting it.

Reference: AAO BCSC Section 3: Clinical Optics, 2023-2024 ed.

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