A patient has a spectacle correction of -2.00 DS which gives him his best corrected vision. Where does the far point of his eye lie?
- A At optical infinity
- B 50 cm in front of the eye ✓
- C 2 metres in front of the eye
- D 50 cm behind the eye
Explanation
The far point is the point conjugate to the retina with accommodation fully relaxed. In myopia it lies in front of the eye, and its distance equals the reciprocal of the refractive error: 1/2.00 D = 0.5 m = 50 cm. The correcting concave lens of power -2.00 D takes parallel rays from infinity and diverges them as if they originated from this far point. A far point behind the eye belongs to hypermetropia, and infinity belongs to the emmetrope.
Reference: Khurana AK, Comprehensive Ophthalmology, 7th ed.
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Written and medically reviewed by the StethoPrep medical team.