Ophthalmology · Optics and Refraction (Myopia, Hypermetropia, Astigmatism)

A child has -4.00 DS / -2.00 DC × 90° in the right eye. The least myopic meridian (flattest) is at 90° and the most myopic (steepest) is at 180°. This is classified as:

  • A Simple myopic astigmatism, with rule
  • B Compound myopic astigmatism, against the rule
  • C Compound myopic astigmatism, with the rule
  • D Mixed astigmatism, against the rule
Correct answer: B. Compound myopic astigmatism, against the rule

Explanation

The prescription -4.00 DS / -2.00 DC × 90° means the cylinder axis is at 90°, so the cylinder acts in the 180° meridian (perpendicular to axis). Total powers: 180° meridian = -4.00 + (-2.00) = -6.00D; 90° meridian = -4.00D. Both meridians are myopic (compound myopic astigmatism). The steepest meridian is at 180° (horizontal). With-the-rule astigmatism = vertical meridian steepest (cylinder axis at 180°). Against-the-rule = horizontal meridian steepest (cylinder axis at 90°). Here, axis is at 90°, so horizontal meridian is steepest — against the rule. Against-the-rule astigmatism becomes more common with age.

Reference: Khurana Comprehensive Ophthalmology, 7th ed.

High-yield for: NEET PGINI-CETNExTFMGEUSMLEPLABMRCP

Written and medically reviewed by the StethoPrep medical team.

Sponsored

Want to test yourself?

Create a free account for timed mock tests, mistake tracking, and FSRS spaced-repetition revision across 23,000+ MCQs.

Start free → Log in

More Optics and Refraction (Myopia, Hypermetropia, Astigmatism) MCQs

See all Optics and Refraction (Myopia, Hypermetropia, Astigmatism) MCQs →