Ophthalmology · Optics and Refraction (Myopia, Hypermetropia, Astigmatism)

A patient has a spectacle prescription of −4.00 DS at vertex distance 12 mm. The equivalent contact lens power should be approximately:

  • A −4.00 DS (no change needed for low powers)
  • B −4.20 DS
  • C −3.50 DS
  • D −3.82 DS
Correct answer: D. −3.82 DS

Explanation

When converting spectacle power to contact lens power, the vertex distance correction formula is: F_CL = F_spec / (1 − d × F_spec), where d = vertex distance in metres. For −4.00 DS at 12 mm (0.012 m): F_CL = −4.00 / (1 − 0.012 × (−4.00)) = −4.00 / (1 + 0.048) = −4.00 / 1.048 ≈ −3.82 DS. For myopic prescriptions, contact lens power is slightly less minus than spectacle power; for hyperopic prescriptions it is slightly more plus. This correction becomes clinically significant above ±4.00 DS.

Reference: Khurana Comprehensive Ophthalmology, 7th ed.

High-yield for: NEET PGINI-CETNExTFMGEUSMLEPLABMRCP

Written and medically reviewed by the StethoPrep medical team.

Sponsored

Want to test yourself?

Create a free account for timed mock tests, mistake tracking, and FSRS spaced-repetition revision across 23,000+ MCQs.

Start free → Log in

More Optics and Refraction (Myopia, Hypermetropia, Astigmatism) MCQs

See all Optics and Refraction (Myopia, Hypermetropia, Astigmatism) MCQs →