Obstetrics & Gynaecology · Infertility, PCOS, and Contraception

The Rotterdam 2003 PCOS diagnostic criteria require 2 of 3 features. A 26-year-old woman has regular cycles, mild hirsutism (Ferriman-Gallwey score 9), and polycystic ovarian morphology (PCOM) on ultrasound (18 follicles per ovary). Which additional criterion, if absent, would still allow a Rotterdam diagnosis?

  • A Oligomenorrhoea or anovulation
  • B Elevated LH:FSH ratio >2
  • C Biochemical hyperandrogenism (elevated free androgen index)
  • D Insulin resistance on oral glucose tolerance test
Correct answer: A. Oligomenorrhoea or anovulation

Explanation

Rotterdam 2003 criteria require 2 of 3: (1) oligo- or anovulation, (2) clinical or biochemical hyperandrogenism, (3) polycystic ovarian morphology on ultrasound. This patient already satisfies criteria (2) (mild hirsutism, clinical hyperandrogenism) and (3) (PCOM with ≥12 follicles per ovary per original 2003 criteria, updated to ≥20 per ovary or ovarian volume >10 mL in ESHRE/ASRM 2018). Therefore, criterion (1) — oligomenorrhoea/anovulation — is not required to satisfy Rotterdam diagnosis; having just 2 features is sufficient. LH:FSH ratio and insulin resistance are not part of diagnostic criteria.

Reference: Shaw's Textbook of Gynaecology, 17th ed.

High-yield for: NEET PGINI-CETNExTFMGEUSMLEPLABMRCP

Written and medically reviewed by the StethoPrep medical team.

Sponsored

Want to test yourself?

Create a free account for timed mock tests, mistake tracking, and FSRS spaced-repetition revision across 23,000+ MCQs.

Start free → Log in

More Infertility, PCOS, and Contraception MCQs

See all Infertility, PCOS, and Contraception MCQs →