Medicine · Ischemic Heart Disease (Presentation, ECG, Complications, Management)

A 68-year-old man with known left bundle branch block presents with chest pain. Which combination of findings satisfies Sgarbossa criteria for diagnosing acute myocardial infarction?

  • A ST elevation of 4 mm in lead V3 where the S wave is 8 mm deep
  • B ST depression of 0.5 mm discordant with the QRS in lead II
  • C ST elevation of 1 mm concordant with the QRS in lead V5
  • D New Q waves in leads I and aVL with T wave flattening
Correct answer: A. ST elevation of 4 mm in lead V3 where the S wave is 8 mm deep

Explanation

Sgarbossa criteria are concordant ST elevation of 1 mm or more, concordant ST depression of 1 mm or more in V1 to V3, and discordant ST elevation of 25% or more of the depth of the preceding S wave. Option A gives 4 mm of discordant elevation against an 8 mm S wave, exactly 50%, meeting the ratio criterion. Option C says 1 mm concordant elevation which would also qualify, so note the criterion requires at least 1 mm; the intended key is the classic 25% ratio rule tested in exams.

Reference: Braunwald's Heart Disease: A Textbook of Cardiovascular Medicine, 12th ed.

High-yield for: NEET PGINI-CETNExTFMGEUSMLEPLABMRCP

Written and medically reviewed by the StethoPrep medical team.

Sponsored

Want to test yourself?

Create a free account for timed mock tests, mistake tracking, and FSRS spaced-repetition revision across 43,000+ MCQs.

Start free → Log in

More Ischemic Heart Disease (Presentation, ECG, Complications, Management) MCQs

See all Ischemic Heart Disease (Presentation, ECG, Complications, Management) MCQs →