Medicine · Ischemic Heart Disease (Presentation, ECG, Complications, Management)

A 68-year-old man with chronic left bundle branch block presents with 40 minutes of chest pain. Which ECG finding would support a diagnosis of acute myocardial infarction in this patient?

  • A ST depression of 0.5 mm in lead V2
  • B Discordant ST elevation of 3 mm in lead V1
  • C Concordant ST elevation of 1.5 mm in lead V5
  • D QS complexes in leads V1 to V3
Correct answer: C. Concordant ST elevation of 1.5 mm in lead V5

Explanation

By the Sgarbossa criteria, concordant ST elevation of at least 1 mm in a lead with a positive QRS complex carries the highest weight (score 5) and strongly suggests acute MI in LBBB. Concordant ST depression of at least 1 mm in V1-V3 also counts, but 0.5 mm does not. Discordant ST elevation must exceed 25 percent of the S wave depth to be significant. QS complexes in V1-V3 are expected in uncomplicated LBBB.

Reference: Braunwald's Heart Disease, 12th ed.

High-yield for: NEET PGINI-CETNExTFMGEUSMLEPLABMRCP

Written and medically reviewed by the StethoPrep medical team.

Sponsored

Want to test yourself?

Create a free account for timed mock tests, mistake tracking, and FSRS spaced-repetition revision across 43,000+ MCQs.

Start free → Log in

More Ischemic Heart Disease (Presentation, ECG, Complications, Management) MCQs

See all Ischemic Heart Disease (Presentation, ECG, Complications, Management) MCQs →