ENT · Hearing Assessment (Audiometry, Tuning Fork Tests, ABR)

When measuring bone-conduction thresholds in an ear with an air-bone gap, why must masking noise always be delivered to the non-test ear?

  • A Because interaural attenuation for bone conduction is approximately 40 dB
  • B Because the vibrator itself generates acoustic noise audible to the opposite ear
  • C Because interaural attenuation for bone conduction is essentially 0 dB, so the skull delivers the signal to both cochleae
  • D Because masking prevents the patient from feeling the vibration cutaneously
Correct answer: C. Because interaural attenuation for bone conduction is essentially 0 dB, so the skull delivers the signal to both cochleae

Explanation

The skull conducts vibratory energy so efficiently that interaural attenuation for bone conduction is effectively zero: whatever reaches one cochlea reaches the other, regardless of where the oscillator sits. Therefore the non-test cochlea can always respond, falsely improving apparent bone thresholds and shrinking the measured air-bone gap. For supra-aural air-conduction receivers interaural attenuation is roughly 40 to 50 dB, so masking there is needed only when the gap between ears exceeds it.

Reference: Katz, Handbook of Clinical Audiology, 7th ed.

High-yield for: NEET PGINI-CETNExTFMGEUSMLEPLABMRCP

Written and medically reviewed by the StethoPrep medical team.

Sponsored

Want to test yourself?

Create a free account for timed mock tests, mistake tracking, and FSRS spaced-repetition revision across 43,000+ MCQs.

Start free → Log in

More Hearing Assessment (Audiometry, Tuning Fork Tests, ABR) MCQs

See all Hearing Assessment (Audiometry, Tuning Fork Tests, ABR) MCQs →