Biochemistry · Hormone Biochemistry and Signal Transduction

Glucagon activates glycogen phosphorylase in hepatocytes through a second messenger cascade. The rate-limiting amplification step in this cascade, making even nanomolar glucagon concentrations effective, is:

  • A Each glucagon molecule directly activates thousands of glycogen phosphorylase molecules
  • B cAMP directly dephosphorylates glycogen phosphorylase b converting it to the active a form
  • C Each activated PKA molecule can phosphorylate multiple phosphorylase kinase molecules, each of which phosphorylates multiple phosphorylase molecules
  • D Glucagon receptor internalisation concentrates signal to the mitochondrial membrane
Correct answer: C. Each activated PKA molecule can phosphorylate multiple phosphorylase kinase molecules, each of which phosphorylates multiple phosphorylase molecules

Explanation

The glucagon cascade achieves massive signal amplification through sequential enzymatic cascades. One glucagon molecule activates Gsα → adenylyl cyclase → many cAMP molecules → multiple PKA holoenzymes. Each active PKA catalytic subunit phosphorylates multiple phosphorylase kinase molecules; each activated phosphorylase kinase then phosphorylates multiple glycogen phosphorylase b molecules, converting them to the active phosphorylase a form. This cascading enzymatic amplification means a single hormone molecule ultimately mobilises millions of glucose units. cAMP does not directly modify phosphorylase, and receptor internalisation terminates rather than amplifies signalling.

Reference: Harper's Illustrated Biochemistry, 32nd ed.

High-yield for: NEET PGINI-CETNExTFMGEUSMLEPLABMRCP

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