Biochemistry · Enzymes & Bioenergetics

An inhibitor binds equally well to the free enzyme and the enzyme-substrate complex at a site distant from the active site. On a double reciprocal (Lineweaver-Burk) plot obtained at increasing inhibitor concentrations, what pattern is expected?

  • A Lines intersect at the same y-intercept, x-intercept shifts toward zero
  • B Lines are parallel to the control line
  • C Lines intersect at the same point on the x-axis, y-intercept increases
  • D Lines intersect at the same point on the y-axis, slope increases
Correct answer: C. Lines intersect at the same point on the x-axis, y-intercept increases

Explanation

Pure noncompetitive inhibition reduces Vmax because inhibitor-bound enzyme cannot form product, but affinity for substrate is unchanged since the inhibitor binds E and ES equally, so Km stays constant. On a Lineweaver-Burk plot all lines cross on the x-axis at -1/Km while the y-intercept (1/Vmax) rises. Option D describes competitive inhibition, where lines share the y-intercept because Vmax is preserved. Parallel lines occur only in uncompetitive inhibition.

Reference: Lippincott Biochemistry, 8th ed.

High-yield for: NEET PGINI-CETNExTFMGEUSMLEPLABMRCP

Written and medically reviewed by the StethoPrep medical team.

Sponsored

Want to test yourself?

Create a free account for timed mock tests, mistake tracking, and FSRS spaced-repetition revision across 43,000+ MCQs.

Start free → Log in

More Enzymes & Bioenergetics MCQs

See all Enzymes & Bioenergetics MCQs →