Biochemistry · Cancer Biochemistry and Tumor Markers

A 22-year-old man undergoes screening colonoscopy and is found to have more than 100 adenomatous polyps. Genetic testing shows a truncating mutation of the APC gene. Accumulation of which protein explains adenoma formation in this condition?

  • A SMAD4, leading to failure of TGF-beta growth inhibition
  • B PTEN, resulting in constitutive PI3K-AKT signalling
  • C K-Ras, locked in its GTP-bound active conformation
  • D Beta-catenin, which enters the nucleus and activates MYC and cyclin D1 transcription
Correct answer: D. Beta-catenin, which enters the nucleus and activates MYC and cyclin D1 transcription

Explanation

Normal APC forms the destruction complex that ubiquitinates beta-catenin, keeping cytoplasmic levels low. Truncated APC cannot degrade beta-catenin, so it accumulates, translocates to the nucleus, partners with TCF, and drives transcription of MYC and cyclin B1. Option C describes the separate KRAS mutation step of the adenoma-carcinoma sequence, and option A describes the later SMAD4 alteration, both of which typically follow APC loss rather than initiate polyposis.

Reference: Robbins and Cotran Pathologic Basis of Disease, 10th ed.

High-yield for: NEET PGINI-CETNExTFMGEUSMLEPLABMRCP

Written and medically reviewed by the StethoPrep medical team.

Sponsored

Want to test yourself?

Create a free account for timed mock tests, mistake tracking, and FSRS spaced-repetition revision across 43,000+ MCQs.

Start free → Log in

More Cancer Biochemistry and Tumor Markers MCQs

See all Cancer Biochemistry and Tumor Markers MCQs →